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Talk:Penman equation

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is someone able to show a worked example for this, I don't know if I am using it correctly. Teeteetee 14:07, 5 May 2006 (UTC)[reply]

I should be able to, since my rain garden simulation model depends on it:)

[edit]

I see nothing unverifiable about the original Penman equation, but I confess this is not the form of Penman's Equation most accurate for vegetation. The FAO56 standard covers that.

Priestly Taylor...

I may talk with my adviser, Bruce N. Wilson at the U of M, to muster a better explanation of this equation and the various forms for plant evapotranspiration (eg. Penman-Monteith). Time is always the issue. BrianAsh


Okay, here the equation is worked out, mostly with help from FAO-56: (http://www.fao.org/docrep/X0490E/x0490e06.htm)
Basically, the crux is to find the atmospheric conductance (m s-1). FAO-56 P-M uses aerodynamic resistance [s m-1], (208/u2) or conductance's inverse, so the formula is otherwise the same if you remove the stomatal resistance terms from FAO-56.
I was seeking the evaporation (sweat) rate for a human, so I discarded the radiation (and latent heat) terms. The initial values for this example are: temperature = 34, dew point = 10, elevation = 10 and wind speed = 10
423.70787202733 ETo reference evapotranspiration [W m-2]
1.1458764954493 rho a mean air density at constant pressure [kg m-3]
1012 cp specific heat of the air [J/(kg·K)]
4.1279690380751 es saturation vapour pressure [kPa],
1.1236872033495 ea actual vapour pressure [kPa],
27.733333333333 ra aerodynamic resistance [s m-1],
0.2298311011042 D slope vapour pressure curve [kPa °C-1],
0.06664547816281 g psychrometric constant [kPa °C-1].


1.1458764954493 rho a=n*28.9/1000
39.649705724888 n=PV/RT
8.3144 R
307 T air temperature at 2 m height [°C],
7.5 u2 wind speed at 2 m height [m s-1],
Baden

--187.132.3.243 (talk) 07:52, 20 March 2010 (UTC)[reply]