Talk:Normal closure (group theory)

This seems wrong. The conjugate closure should give the union of all conjugacy classes containing S, not the smallest normal subgroup containing S. For example, take S = { x } with x != 0, then the conjugate closure of S in (R,+) is just S. However S is not a subgroup of R. The statement would be true if S contained the identity however. — Preceding unsigned comment added by 76.204.99.5 (talk) 22:12, 6 May 2011 (UTC)[reply]

The conjugate closure is the subgroup GENERATED by S^G (thus written $<S^{G}>$ ). I made the same error about S={}. --72.226.86.106 (talk) 16:50, 7 September 2014 (UTC)[reply]

As usual, the question is, what do independent reliable sources say? Deltahedron (talk) 17:03, 7 September 2014 (UTC)[reply]