Talk:Hofmann elimination

Chemistry Mid‑importance

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Pharmacology Mid‑importance

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Untitled

I've removed the first scheme because it was confusing; the text states that the less substituted alkene should form but the scheme says otherwise.

would be good. —Preceding unsigned comment added by 149.171.6.249 (talk) 08:25, 7 April 2008 (UTC)[reply]

No, the alkene in the cartoon is symmetrical, only shows the elimination but not the selectivity V8rik (talk) 17:00, 7 April 2008 (UTC)[reply]

Thanks for the reply. But what is the reason for showing the minor product rather than the major product? As I said, it's highly confusing and the scheme needs to be changed so that it's in line with the text. —Preceding unsigned comment added by 60.241.170.43 (talk) 15:52, 13 April 2008 (UTC)[reply]

Also I don't get what the alkene being symmetrical has to do with the selectivity? please explain, cheers. —Preceding unsigned comment added by 60.241.170.43 (talk) 15:54, 13 April 2008 (UTC)[reply]

I have updated the image and the text so that should remove the confusion, please note that the main image only shows how the reaction proceeds. V8rik (talk) 16:56, 13 April 2008 (UTC) PS sign your comments by adding 4 tildes (~) in a row.[reply]

Why does the cartoon indicate stereochemistry associated with a cyclic double bond hydrogens? Those are NOT chiral centers. —Preceding unsigned comment added by 76.20.63.162 (talk) 19:34, 8 December 2008 (UTC)[reply]
- Has nothing to do with chirality => reflects presence of cis and trans isomers. V8rik (talk) 21:40, 8 December 2008 (UTC)[reply]