Talk:Complex-base system

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Image compression

There is a discussion about the use of this idea in image compression. [1]

periodic?

I preserved the phrase "is one of periodic cases" – but what does it mean? —Tamfang (talk) 00:32, 5 December 2008 (UTC)[reply]

Seeing no clarification, I'll remove the phrase but keep the footnote. —Tamfang (talk) 04:45, 16 December 2009 (UTC)[reply]

improve translation

Listed below are those of the system (as a special case shown above systems) and shows code numbers 2, -2, -1.

Whatever language this came from, it's not clear in English. Can someone improve it? —Tamfang (talk) 17:38, 3 May 2011 (UTC)[reply]

/* Complex_base_systems#In general */

General notation:
Instead of:

<\rho =\pm i{\sqrt {2}},[0,1]>

I would like to propose the notation:

{\bigg \langle }\rho =\pm i{\sqrt {2}},\{0,1\}{\bigg \rangle }

.

The $\{0,1\}$ because it is a set, so that one can say: set of digits $D:=\{0,1\}$ and ${\big \langle }\rho =\pm i{\sqrt {2}},D{\big \rangle }$ , and the ${\big \langle }...{\big \rangle }$ because of optics.

Text below:
Shouldn't one split up

$<\rho ={\sqrt {2}}e^{\pm i\pi /2},B_{2}>$ , example, $<\rho =[-1\pm i],[0,1]>$ (see also section "Base −1±i" below).

into

${\bigg \langle }\rho ={\sqrt {2}}e^{\pm i\pi /2},B_{2}{\bigg \rangle }$ , example, ${\big \langle }\rho =(\pm i{\sqrt {2}}),\{0,1\}{\big \rangle }$ .

and

${\bigg \langle }\rho ={\sqrt {2}}e^{\pm 3i\pi /4},B_{2}{\bigg \rangle }$ , example, ${\big \langle }\rho =(-1\pm i),\{0,1\}{\big \rangle }$ (see also section "Base −1±i" below). -- Nomen4Omen (talk) 11:42, 2 August 2011 (UTC)[reply]

Added reference

The inline reference to Penney's paper was wrong - it linked to some other paper. Unfortunately the system for inline references on Wikipedia is complicated enough that I don't have time to figure out how it works! So I added the bibliographical information on Penney's paper to the 'References' section in a very crude way. I hope someone can fix things up. John Baez (talk) 16:07, 8 November 2012 (UTC)[reply]

mixed radix

I've experimented with mixing the radices -1+i and -1-i. If they alternate, the rounding domain is a parallelogram with vertices at 0, 1, i, -1+i (or the conjugates); other sequences give other pretty shapes. —Tamfang (talk) 03:46, 3 March 2019 (UTC)[reply]

You mean radices alternating between -1+i and -1-i ?

Isn't a0*(-1+i)+a1*(-1+i)*(-1-i) = a0*(-1+i)+a1*2 very close to

{\big \langle }2i,\{0,-1+i,2,1+i\}{\big \rangle }

? Which looks almost like the Quater-imaginary base system

{\big \langle }2i,\{0,1,2,3\}{\big \rangle }

? --Nomen4Omen (talk) 11:04, 3 March 2019 (UTC)[reply]

animation

There may be a place for this – with a better caption – but not filling the top of the page. —Tamfang (talk) 06:14, 4 May 2024 (UTC)[reply]

rounding

The rounding region of an integer – i.e., a set of complex (non-integer) numbers that share the integer part of their representation in this system – has in the complex plane a fractal shape: the twindragon.

I would call it the truncation region. Rounding, it seems to me, is an arithmetic operation independent of base. —Tamfang (talk) 18:38, 1 July 2024 (UTC)[reply]