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Taintsville, Florida

Coordinates: 28°38′48″N 81°08′12″W / 28.64667°N 81.13667°W / 28.64667; -81.13667
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Taintsville
Taintsville is located in Seminole County, Florida
Taintsville
Taintsville
Location within Florida
Coordinates: 28°38′48″N 81°08′12″W / 28.64667°N 81.13667°W / 28.64667; -81.13667
CountryUnited States
StateFlorida
CountySeminole
Population
 • Estimate 
({{{pop_est_as_of}}})
80
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
Area code(s)407, 689 & 321

Taintsville is an unincorporated community in Seminole County, Florida, United States, located between Oviedo and Chuluota. On December 14, 1971, it was formally designated as the Village of Taintsville by Seminole County.[1] The population is about 80 people.[2]

The community's name was derived by residents saying "t ain't" Oviedo and "t ain't" Chuluota.[3]

References

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  1. ^ Seminole County Board of County Commission resolution of 12/14/1971 designating area as the Village of Taintsville
  2. ^ Byrne, Jason (November 8, 2021). "The Village of Taintsville". Medium. Retrieved September 22, 2022.
  3. ^ Robinson, Jim (2012). Images of America: Around Oviedo. Charleston, South Carolina: Arcadia Publishing. p. 9. ISBN 978-0-7385-9060-8. Retrieved December 18, 2013.
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