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Sand Creek Township, Jennings County, Indiana

Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694
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Sand Creek Township
Location in Jennings County
Location in Jennings County
Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694
CountryUnited States
StateIndiana
CountyJennings
Government
 • TypeIndiana township
Area
 • Total27.95 sq mi (72.4 km2)
 • Land27.72 sq mi (71.8 km2)
 • Water0.23 sq mi (0.6 km2)  0.82%
Elevation
725 ft (221 m)
Population
 (2020)
 • Total859
 • Density31/sq mi (12/km2)
GNIS feature ID0453833

Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2020 census, its population was 859 (down from 872 at 2010[1]) and it contained 364 housing units.[2]

Historical population
CensusPop.Note
18901,039
1900992−4.5%
1910819−17.4%
1920687−16.1%
1930529−23.0%
194061416.1%
1950602−2.0%
19606457.1%
197075216.6%
19808036.8%
1990714−11.1%
200081814.6%
20108726.6%
2020859−1.5%
Source: US Decennial Census[3]

Geography

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According to the 2010 census, the township has a total area of 27.95 square miles (72.4 km2), of which 27.72 square miles (71.8 km2) (or 99.18%) is land and 0.23 square miles (0.60 km2) (or 0.82%) is water.[1] The streams of Bear Creek, Fish Creek, Ice Creek, Millstone Creek, Poplar Root Creek and Rock Creek run through this township.

Unincorporated towns

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Adjacent townships

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Cemeteries

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The township contains three cemeteries: Bear Creek, Day and Fish Creek.

Major highways

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References

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  1. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
  2. ^ "Explore Census Data". data.census.gov. Retrieved April 10, 2024.
  3. ^ "Township Census Counts: STATS Indiana".
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