Let and be Banach spaces, a closed linear operator whose domain is dense in and the transpose of . The theorem asserts that the following conditions are equivalent:
Where and are the null space of and , respectively.
Note that there is always an inclusion , because if and , then . Likewise, there is an inclusion . So the non-trivial part of the above theorem is the opposite inclusion in the final two bullets.
Several corollaries are immediate from the theorem. For instance, a densely defined closed operator as above has if and only if the transpose has a continuous inverse. Similarly, if and only if has a continuous inverse.
Since the graph of T is closed, the proof reduces to the case when is a bounded operator between Banach spaces. Now, factors as . Dually, is
Now, if is closed, then it is Banach and so by the open mapping theorem, is a topological isomorphism. It follows that is an isomorphism and then . (More work is needed for the other implications.)