Clinton, Ohio County, West Virginia
Clinton | |
|---|---|
  Clinton Location within the state of West Virginia  Clinton Clinton (the United States) | |
| Coordinates: 40°7′26″N 80°37′34″W / 40.12389°N 80.62611°W | |
| Country | United States |
| State | West Virginia |
| County | Ohio |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
Clinton is an unincorporated community in Ohio County, West Virginia, United States. It lies at an elevation of 968 feet (295 m).[1]
Clinton bears the name of a pioneer settler.[2]
References
[edit]- ^ "Clinton". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved August 16, 2024.
- ^ Kenny, Hamill (1945). West Virginia Place Names: Their Origin and Meaning, Including the Nomenclature of the Streams and Mountains. Piedmont, WV: The Place Name Press. p. 176.
Municipalities and communities of Ohio County, West Virginia, United States | ||
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| Unincorporated communities | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
 | This article about a location in Ohio County, West Virginia is a stub. You can help Wikipedia by expanding it. |