Buck Hill (Herkimer County, New York)
| Buck Hill | |
|---|---|
  Buck Hill Location of Buck Hill within New York  Buck Hill Buck Hill (the United States) | |
| Highest point | |
| Elevation | 928 feet (283 m) |
| Coordinates | 43°14′13″N 75°03′31″W / 43.23694°N 75.05861°W[1] |
| Geography | |
| Location | N of Poland, New York, U.S. |
| Topo map | USGS Newport |
Buck Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, north of Poland.
References
[edit]- ^ "Buck Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2017-12-08.