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2019 Kiskút Open – Doubles

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Doubles
2019 Kiskút Open
Final
ChampionsRomania Irina Bara
Belgium Maryna Zanevska
Runners-upUzbekistan Akgul Amanmuradova
Romania Elena Bogdan
Score3–6, 6–2, [10–8]
Events
Singles Doubles
Kiskút Open · 2020 →

This was the first edition of the tournament.[1]

Irina Bara and Maryna Zanevska won the title, defeating Akgul Amanmuradova and Elena Bogdan in the final, 3–6, 6–2, [10–8].

Seeds

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Draw

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Key

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Draw

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First round Quarterfinals Semifinals Final
1 Spain G García Pérez
Hungary F Stollár
3 0r
  Romania I Bara
Belgium M Zanevska
6 1 Romania I Bara
Belgium M Zanevska
6 6
  Hungary RL Jani
Argentina P Ormaechea
5 6 [10] Hungary RL Jani
Argentina P Ormaechea
2 3
  Poland M Chwalińska
Hungary A Nagy
7 3 [7] Romania I Bara
Belgium M Zanevska
77 6
3 Romania N Dascălu
Montenegro D Kovinić
w/o 3 Romania N Dascălu
Montenegro D Kovinić
63 1
  Slovakia V Juhászová
Austria M Klaffner
3 Romania N Dascălu
Montenegro D Kovinić
6 6
  Hungary A Bondár
Slovakia R Šramková
0 6 [10] Hungary A Bondár
Slovakia R Šramková
4 2
  Brazil G Cé
Switzerland S Waltert
6 4 [8] Romania I Bara
Belgium M Zanevska
3 6 [10]
  Ukraine M Chernyshova
Slovakia C Škamlová
w/o 4 Uzbekistan A Amanmuradova
Romania E Bogdan
6 2 [8]
WC Hungary Á Bukta
Brazil T Pereira
Ukraine M Chernyshova
Slovakia C Škamlová
2 64
WC Hungary B Békefi
Hungary D Drahota-Szabó
3 4 4 Uzbekistan A Amanmuradova
Romania E Bogdan
6 77
4 Uzbekistan A Amanmuradova
Romania E Bogdan
6 6 4 Uzbekistan A Amanmuradova
Romania E Bogdan
2 6 [10]
  Romania M Bulgaru
Romania IG Ghioroaie
6 6 2 Russia A Anshba
Czech Republic A Dețiuc
6 4 [4]
  Czech Republic J Marková
Chile D Seguel
4 2 Romania M Bulgaru
Romania IG Ghioroaie
2 3
  Slovenia N Potočnik
Slovenia N Radišič
4 3 2 Russia A Anshba
Czech Republic A Dețiuc
6 6
2 Russia A Anshba
Czech Republic A Dețiuc
6 6

References

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  1. ^ "W60 Székesfehérvár". www.itftennis.com.