2017 RBC Pro Challenge – Doubles
Appearance
Doubles | |
---|---|
2017 RBC Pro Challenge | |
Champion | Jessica Pegula Taylor Townsend |
Runner-up | Jamie Loeb Rebecca Peterson |
Score | 6–4, 6–1 |
This was the first edition of the tournament.
Jessica Pegula and Taylor Townsend won the title, defeating Jamie Loeb and Rebecca Peterson in the final, 6–4, 6–1.
Seeds
[edit]- Irina Falconi / María Irigoyen (semifinals)
- Ashley Weinhold / Caitlin Whoriskey (semifinals)
- Sophie Chang / Alexandra Mueller (quarterfinals)
- Sofia Kenin / Anastasiya Komardina (first round)
Draw
[edit]Key
[edit]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | I Falconi M Irigoyen | 6 | 3 | ||||||||||||||||||||||||
K Galieva S Karatantcheva | 5 | 6 | [9] | A Gabueva S Vickery | 3 | 0r | |||||||||||||||||||||
A Gabueva S Vickery | 7 | 4 | [11] | 1 | I Falconi M Irigoyen | 3 | 6 | [11] | |||||||||||||||||||
4 | S Kenin A Komardina | 6 | 3 | [5] | J Loeb R Peterson | 6 | 3 | [13] | |||||||||||||||||||
J Loeb R Peterson | 3 | 6 | [10] | J Loeb R Peterson | 6 | 6 | |||||||||||||||||||||
A Uzcátegui A Zhu | w/o | A Uzcátegui A Zhu | 4 | 4 | |||||||||||||||||||||||
PC Gonçalves S Marand | J Loeb R Peterson | 4 | 1 | ||||||||||||||||||||||||
J Pegula T Townsend | 6 | 5 | [10] | J Pegula T Townsend | 6 | 6 | |||||||||||||||||||||
JA Asghar C Kung | 2 | 7 | [6] | J Pegula T Townsend | 6 | 4 | [10] | ||||||||||||||||||||
S Mardarenko I Račika-Račko | 2 | 0 | 3 | S Chang A Mueller | 4 | 6 | [6] | ||||||||||||||||||||
3 | S Chang A Mueller | 6 | 6 | J Pegula T Townsend | 6 | 6 | |||||||||||||||||||||
U Eikeri E Kostova | 6 | 6 | 2 | A Weinhold C Whoriskey | 3 | 4 | |||||||||||||||||||||
S Abrams J Vulpio | 0 | 3 | U Eikeri E Kostova | 2 | 5 | ||||||||||||||||||||||
K Derienzo J Robinson | 2 | 3 | 2 | A Weinhold C Whoriskey | 6 | 7 | |||||||||||||||||||||
2 | A Weinhold C Whoriskey | 6 | 6 |