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2014 ATP Shenzhen Open – Doubles

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Doubles
2014 ATP Shenzhen Open
Final
ChampionsNetherlands Jean-Julien Rojer
Romania Horia Tecău
Runners-upAustralia Sam Groth
Australia Chris Guccione
Score6–4, 7–6(7–4)
Events
Singles Doubles
ATP Shenzhen Open · 2015 →

This was the first edition of the tournament.

Jean-Julien Rojer and Horia Tecău won the title, defeating Sam Groth and Chris Guccione in the final, 6–4, 7–6(7–4).

Seeds

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Draw

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Key

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Draw

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First round Quarterfinals Semifinals Final
1 Netherlands J-J Rojer
Romania H Tecău
6 6
United Kingdom C Fleming
Sweden R Lindstedt
2 1 1 Netherlands J-J Rojer
Romania H Tecău
6 5 [10]
Russia E Donskoy
Russia T Gabashvili
6 6 Russia E Donskoy
Russia T Gabashvili
4 7 [7]
WC China Z Qiu
China R Te
3 3 1 Netherlands J-J Rojer
Romania H Tecău
3 6 [10]
3 India R Bopanna
Pakistan A-u-H Qureshi
6 4 [10] Colombia S Giraldo
New Zealand M Venus
6 1 [5]
Australia M Ebden
Italy A Seppi
4 6 [7] 3 India R Bopanna
Pakistan A-u-H Qureshi
4 64
Argentina M González
Argentina J Mónaco
6 3 [4] Colombia S Giraldo
New Zealand M Venus
6 77
Colombia S Giraldo
New Zealand M Venus
4 6 [10] 1 Netherlands J-J Rojer
Romania H Tecău
6 77
Australia S Groth
Australia C Guccione
6 6 Australia S Groth
Australia C Guccione
4 64
WC China B Ouyang
China A Wang
3 4 Australia S Groth
Australia C Guccione
67 77 [10]
United Kingdom J Delgado
Luxembourg G Müller
3 64 4 Poland M Fyrstenberg
Belarus M Mirnyi
79 64 [4]
4 Poland M Fyrstenberg
Belarus M Mirnyi
6 77 Australia S Groth
Australia C Guccione
77 6
Sweden J Brunström
United States N Monroe
63 6 [10] 2 Colombia JS Cabal
Colombia R Farah
65 4
Belarus S Betov
Belarus A Bury
77 3 [5] Sweden J Brunström
United States N Monroe
6 4 [5]
Alt Switzerland M Chiudinelli
Slovakia L Lacko
1 1 2 Colombia JS Cabal
Colombia R Farah
4 6 [10]
2 Colombia JS Cabal
Colombia R Farah
6 6

References

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