2005 BCR Open Romania – Doubles

Doubles
2005 BCR Open Romania
Champions	José Acasuso Sebastián Prieto
Runners-up	Victor Hănescu Andrei Pavel
Score	6–3, 4–6, 6–3

Main article: 2005 BCR Open Romania

Lucas Arnold Ker and Mariano Hood were the defending champions, but Arnold Ker did not compete this year. Hood teamed up with Martín García and lost in the quarterfinals to Juan Ignacio Chela and Luis Horna.

José Acasuso and Sebastián Prieto won the title by defeating Victor Hănescu and Andrei Pavel 6–3, 4–6, 6–3 in the final.

Seeds

1. Martín García / Mariano Hood (quarterfinals)
2. Julian Knowle / Michael Kohlmann (first round)
3. José Acasuso / Sebastián Prieto (champions)
4. Mariusz Fyrstenberg / Marcin Matkowski (quarterfinals)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• SE = Special exempt
• PR = Protected ranking
• ITF = ITF entry
• JE = Junior exempt
• w/o = Walkover
• r = Retired
• d = Defaulted
• SR = Special ranking

Draw

	First round							Quarterfinals							Semifinals							Final
	1	M García M Hood	6	56	6
	WC	V Ioniță R Sabău	1	68	2			1	M García M Hood	3	3
		JI Chela L Horna	6	6					JI Chela L Horna	6	6
		T Behrend A Waske	2	2												JI Chela L Horna	3	4
	3	J Acasuso S Prieto	6	6											3	J Acasuso S Prieto	6	6
		J Coetzee C Haggard	4	4				3	J Acasuso S Prieto	6	6
		F Mayer R Wassen	6	67					F Mayer R Wassen	1	2
		PH Mathieu R Rochus	4	51																		3	J Acasuso S Prieto	6	4	6
		V Hănescu A Pavel	6	67																			V Hănescu A Pavel	3	6	3
		P Pála D Škoch	4	53					V Hănescu A Pavel	6	67
		N Almagro A Martín	2	2				4	M Fyrstenberg M Matkowski	2	53
	4	M Fyrstenberg M Matkowski	6	6												V Hănescu A Pavel	6	6
	WC	I Moldovan G Moraru	6	6											WC	I Moldovan G Moraru	4	4
		C Berlocq M Puerta	1	2				WC	I Moldovan G Moraru	610	6
		D Sanguinetti T Vanhoudt	6	67					D Sanguinetti T Vanhoudt	58	4
	2	J Knowle M Kohlmann	4	50

External links

• Official results archive (ATP)
• Official results archive (ITF)