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1999 ATP Tour World Championships – Doubles

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Doubles
1999 ATP Tour World Championships
Final
ChampionsCanada Sébastien Lareau
United States Alex O'Brien
Runners-upIndia Mahesh Bhupathi
India Leander Paes
Score6–3, 6–2, 6–2
Details
Draw8
Events
Singles Doubles
← 1998 · ATP Tour World Championships · 2000 →

Sébastien Lareau and Alex O'Brien defeated Mahesh Bhupathi and Leander Paes in the final, 6–3, 6–2, 6–2 to win the doubles tennis title at the 1999 ATP Tour World Championships.[1]

Jacco Eltingh and Paul Haarhuis were the reigning champions, but did not compete together in 1999. Eltingh retired from the sport on November 22, 1998; Haarhuis qualified with Jared Palmer, but was eliminated in the round-robin stage.

Seeds

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  1. India Mahesh Bhupathi / India Leander Paes (final)
  2. Australia Todd Woodbridge / Australia Mark Woodforde (semifinals)
  3. South Africa Ellis Ferreira / United States Rick Leach (round robin)
  4. Canada Sébastien Lareau / United States Alex O'Brien (champions)
  5. South Africa David Adams / South Africa John-Laffnie de Jager (round robin, withdrew due to a flu of de Jager)
  6. Zimbabwe Wayne Black / Australia Sandon Stolle (semifinals)
  7. Netherlands Paul Haarhuis / United States Jared Palmer (round robin)
  8. South Africa Piet Norval / Zimbabwe Kevin Ullyett (round robin)
  9. Czech Republic Jiří Novák / Czech Republic David Rikl (round robin)

Draw

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Key

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Finals

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Semifinals Final
            
1 India Mahesh Bhupathi
India Leander Paes
5 6 7
2 Australia Todd Woodbridge
Australia Mark Woodforde
7 2 5
1 India Mahesh Bhupathi
India Leander Paes
3 2 2    
4 Canada Sébastien Lareau
United States Alex O'Brien
6 6 6    
4 Canada Sébastien Lareau
United States Alex O'Brien
6 7  
6 Zimbabwe Wayne Black
Australia Sandon Stolle
3 5  

Gold group

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  India Bhupathi
India Paes
South Africa Ferreira
United States Leach
Zimbabwe Black
Australia Stolle
South Africa Norval
Zimbabwe Ullyett
RR
W–L
Set
W–L
Game
W–L
Standings
1 India Mahesh Bhupathi
India Leander Paes
6–4, 6–4 7–6(7–5), 5–7, 2–6 7–6(7–1), 6–3 2–1 5–2 39–36 2
3 South Africa Ellis Ferreira
United States Rick Leach
4–6, 4–6 6–3, 6–2 3–6, 3–6 1–2 2–4 26–29 4
6 Zimbabwe Wayne Black
Australia Sandon Stolle
6–7(5–7), 7–5, 6–2 3–6, 2–6 7–6(7–5), 6–1 2–1 4–3 37–33 1
8 South Africa Piet Norval
Zimbabwe Kevin Ullyett
6–7(1–7), 3–6 6–3, 6–3 6–7(5–7), 1–6 1–2 2–4 28–32 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

Green group

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  Australia Woodbridge
Australia Woodforde
Canada Lareau
United States O'Brien
South Africa Adams
South Africa de Jager
Czech Republic Novák
Czech Republic Rikl
Netherlands Haarhuis
United States Plamer
RR
W–L
Set
W–L
Game
W–L
Standings
2 Australia Todd Woodbridge
Australia Mark Woodforde
7–6(7–3), 6–4 6–2, 6–4
(w/ Novák / Rikl)
6–4, 6–2 3–0 6–0 37–22 1
4 Canada Sébastien Lareau
United States Alex O'Brien
6–7(3–7), 4–6 6–2, 7–6(7–5)
(w/ Adams / de Jager)
7–6(7–1), 6–2 2–1 4–2 36–29 2
5
9
South Africa David Adams
South Africa John-Laffnie de Jager
Czech Republic Jiří Novák
Czech Republic David Rikl
2–6, 4–6
(w/ Novák / Rikl)
2–6, 6–7(5–7)
(w/ Adams / de Jager)
4–6, 5–7
(w/ Adams / de Jager)
0–2
0–1
0–4
0–2
17–26
6–12
4
5
7 Netherlands Paul Haarhuis
United States Jared Palmer
4–6, 2–6 6–7(1–7), 2–6 6–4, 7–5
(w/ Adams / de Jager)
1–2 2–4 27–34 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

References

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  1. ^ "1999 ATP Tour World Championships – Doubles results". Association of Tennis Professionals (ATP).