From Wikipedia, the free encyclopedia
1993 tennis event results
Andrei Medvedev was the defending champion, but did not compete this year.
Sergi Bruguera won the title by defeating Diego Nargiso 7–5, 6–2 in the final.[1][2]
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Grand Slam events | |
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ATP Championship Series, Single Week | |
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ATP Championship Series |
- Milan (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- Stuttgart Indoor (S, D)
- Barcelona (S, D)
- Stuttgart Outdoor (S, D)
- Tokyo Outdoor (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Sydney Indoor (S, D)
- Tokyo Indoor (S, D)
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ATP World Series |
- Adelaide (S, D)
- Kuala Lumpur I (S, D)
- Doha (S, D)
- Jakarta (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Dubai (S, D)
- Marseille (S, D)
- San Francisco (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Mexico City (S, D)
- Copenhagen (S, D)
- Zaragoza (S, D)
- Casablanca (S, D)
- Osaka (S, D)
- Estoril (S, D)
- Durban (S, D)
- Hong Kong (S, D)
- Nice (S, D)
- Charlotte (S, D)
- Seoul (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Madrid (S, D)
- Tampa (S, D)
- Coral Springs (S, D)
- Bologna (S, D)
- Florence (S, D)
- London/Queen's Club (S, D)
- Rosmalen (S, D)
- Halle (S, D)
- Genoa (S, D)
- Manchester (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Hilversum (S, D)
- Kitzbühel (S, D)
- Prague (S, D)
- Los Angeles (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Schenectady (S, D)
- Umag (S, D)
- Bucharest (S, D)
- Bordeaux (S, D)
- Palermo (S, D)
- Kuala Lumpur II (S, D)
- Basel (S, D)
- Toulouse (S, D)
- Athens (S, D)
- Bolzano (S, D)
- Tel Aviv (S, D)
- Vienna (S, D)
- Lyon (S, D)
- Beijing (S, D)
- Santiago (S, D)
- São Paulo (S, D)
- Buenos Aires (S, D)
- Moscow (S, D)
- Antwerp (S, D)
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Team events | |
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