Jump to content

1978 Virginia Slims of Philadelphia – Doubles

From Wikipedia, the free encyclopedia

Doubles
1978 Virginia Slims of Philadelphia
Final
ChampionsAustralia Kerry Reid
Australia Wendy Turnbull
Runners-upFrance Françoise Dürr
United Kingdom Virginia Wade
Score6–3, 7–5
Details
Draw14
Seeds4
Events
Singles Doubles
← 1977 · Advanta Championships of Philadelphia · 1979 →

Françoise Dürr and Virginia Wade were the defending champions, but lost in the final to Kerry Reid and Wendy Turnbull. The score was 6–3, 7–5.

Seeds

[edit]

Draw

[edit]

Key

[edit]

Draw

[edit]
First round Quarterfinals Semifinals Final
1 Australia K Reid
Australia W Turnbull
6 6
United Kingdom G Coles
United States Z Liess
4 1 1 Australia K Reid
Australia W Turnbull
6 6
United States B Potter
West Germany R Tomanová
62 2 United States L Antonoplis
United States P Teeguarden
4 2
United States L Antonoplis
United States P Teeguarden
75 6 1 Australia K Reid
Australia W Turnbull
6 6
4 United States R Casals
United States J Russell
6 6 4 United States R Casals
United States J Russell
4 3
Sweden H Anliot
Czechoslovakia R Maršíková
4 3 4 United States R Casals
United States J Russell
6 3 7
United States T Austin
Netherlands B Stöve
3 6 5
1 Australia K Reid
Australia W Turnbull
6 7
United States L duPont
United States K May
7 6 3 France F Dürr
United Kingdom V Wade
3 5
United Kingdom M Tyler
South Africa Y Vermaak
5 4 United States L duPont
United States K May
6 0 4
West Germany K Ebbinghaus
Romania F Mihai
2 0 3 France F Dürr
United Kingdom V Wade
2 6 6
3 France F Dürr
United Kingdom V Wade
6 6 3 France F Dürr
United Kingdom V Wade
6 7
Australia D Fromholtz
Australia L Hunt
2 5 2 United States J Newberry
United States K Shaw
4 5
Socialist Federal Republic of Yugoslavia M Jaušovec
Romania V Ruzici
6 7 Socialist Federal Republic of Yugoslavia M Jaušovec
Romania V Ruzici
6 2 6
2 United States J Newberry
United States K Shaw
4 6 7
[edit]