Jump to content

1961 Wimbledon Championships – Girls' singles

From Wikipedia, the free encyclopedia

Girls' singles
1961 Wimbledon Championships
Final
ChampionSoviet Union Galina Baksheeva
Runner-upUnited States Katherine Chabot
Score6–4, 8–6
Details
Draw18
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1960 · Wimbledon Championships · 1962 →

Galina Baksheeva defeated Katherine Chabot in the final, 6–4, 8–6 to win the girls' singles tennis title at the 1961 Wimbledon Championships.[1]

Draw

[edit]

Key

[edit]

Finals

[edit]
Semifinals Final
          
United States Katherine Chabot 6 6
Mexico Patricia Reyes 0 0
United States Katherine Chabot 4 6
Soviet Union Galina Baksheeva 6 8
United Kingdom April O'Neill 3 1
Soviet Union Galina Baksheeva 6 6

Top half

[edit]
First round Second round Quarterfinals Semifinals
United States Katherine Chabot 6 6
Republic of Ireland B Burke 0 0
United States K Chabot 6 6
Denmark B Grage 0 0
Federation of Rhodesia and Nyasaland Jenny Morris 4 3
Denmark Birgit Grage 6 6
United States K Chabot 6 6
Mexico P Reyes 0 0
Mexico Patricia Reyes 6 1 7
Austria T Steinhardt 1 6 5
Mexico P Reyes 1 6 6
Poland D Makulska 6 2 3
India S Raphael w/o
Socialist Federal Republic of Yugoslavia T Kokeza w/o Poland D Makulska
Poland D Makulska

Bottom half

[edit]
First round Second round Quarterfinals Semifinals
Netherlands Elsie Spruyt 1 9 3
France Chantal Langanay 6 7 6 France C Langanay 6 6
Sweden Ulla Sandulf 3 2
France C Langanay 8 2
United Kingdom A O'Neill 10 6
Belgium C Loeys 4 3
United Kingdom April O'Neill 6 6
United Kingdom A O'Neill 3 1
Soviet Union G Baksheeva 6 6
Norway Liv Paldan 1 6 2
West Germany R Stollberg 6 1 6
West Germany R Stollberg 4 2
Soviet Union G Baksheeva 6 6
Switzerland S Frolicher 1 2
Soviet Union Galina Baksheeva 6 6

References

[edit]
  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
[edit]