1956 U.S. National Championships – Women's singles
Appearance
Women's singles | |
---|---|
1956 U.S. National Championships | |
Champion | Shirley Fry[1] |
Runner-up | Althea Gibson[1] |
Score | 6–3, 6–4 |
Seeds | 8 |
First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]
Seeds
[edit]The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.
- Shirley Fry (champion)
- Althea Gibson (finalist)
- Louise Brough (quarterfinals)
- Dorothy Knode (quarterfinals)
- Margaret duPont (quarterfinals)
- Shirley Bloomer (semifinals)
- Betty Pratt (semifinals)
- Darlene Hard (quarterfinals)
Draw
[edit]Key
[edit]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- r = Retired
Final eight
[edit]Quarterfinals | Semifinals | Finals | ||||||||||||||||||
1 | Shirley Fry | 6 | 4 | 6 | ||||||||||||||||
5 | Margaret duPont | 2 | 6 | 3 | ||||||||||||||||
1 | Shirley Fry | 6 | 6 | |||||||||||||||||
6 | Shirley Bloomer | 4 | 4 | |||||||||||||||||
6 | Shirley Bloomer | 6 | 6 | |||||||||||||||||
3 | Louise Brough | 3 | 3 | |||||||||||||||||
1 | Shirley Fry | 6 | 6 | |||||||||||||||||
2 | Althea Gibson | 3 | 4 | |||||||||||||||||
4 | Dorothy Knode | 6 | 0 | 2 | ||||||||||||||||
7 | Betty Pratt | 4 | 6 | 6 | ||||||||||||||||
8 | Betty Pratt | 1 | 8 | |||||||||||||||||
2 | Althea Gibson | 6 | 10 | |||||||||||||||||
8 | Darlene Hard | 7 | 1 | |||||||||||||||||
2 | Althea Gibson | 9 | 6 |
References
[edit]- ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
- ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
- ^ "National Tennis Championships Opens Today". The Free Lance–Star. AP. August 31, 1956. p. 12.