Jump to content

1955 Wimbledon Championships – Girls' singles

From Wikipedia, the free encyclopedia

Girls' singles
1955 Wimbledon Championships
Final
ChampionUnited Kingdom Sheila Armstrong
Runner-upFrance Béatrice de Chambure
Score6–2, 6–4
Details
Draw12
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1954 · Wimbledon Championships · 1956 →

Sheila Armstrong defeated Béatrice de Chambure in the final, 6–2, 6–4 to win the girls' singles tennis title at the 1955 Wimbledon Championships.[1]

Draw

[edit]

Key

[edit]

Draw

[edit]
First round Quarterfinals Semifinals Final
Denmark T Dahl 0 3
Australia W Middleton 6 6
Australia W Middleton 4 4
France Béatrice de Chambure 6 6 France Béatrice de Chambure 6 6
Republic of Ireland Gene Hogan 0 0 France Béatrice de Chambure 6 6
West Germany G Stelges 4 10 3 Netherlands Fredy Marinkelle 0 1
Netherlands Fredy Marinkelle 6 8 6 France Béatrice de Chambure 2 4
United Kingdom Sheila Armstrong 6 6 United Kingdom Sheila Armstrong 6 6
Norway B Lorentzen 0 1 United Kingdom Sheila Armstrong 6 7
Jamaica D Crampton 7 2 Belgium MN Fossion 1 5
Belgium MN Fossion 9 6 United Kingdom Sheila Armstrong 6 6
South Africa Valerie Koortzen 3 2
South Africa Valerie Koortzen 6 6
Sweden L Engdahl 0 2

References

[edit]
  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
[edit]