1938 Australian Championships – Women's singles

First-seeded Dorothy Bundy defeated Dorothy Stevenson 6–3, 6–2, in the final to win the women's singles tennis title at the 1938 Australian Championships.^[1]

Seeds

The seeded players are listed below. Dorothy Bundy is the champion; others show the round in which they were eliminated.

^ "Americans invincible". The Age. No. 25, 831. Victoria, Australia. 31 January 1938. p. 15 – via National Library of Australia.

Preceded by 1937 U.S. National Championships – Women's singles	Grand Slam women's singles	Succeeded by 1938 French Championships – Women's singles

v t e Australian Open women's singles drawsheets
Pre Open Era	1922 1923 1924 1925 1926 1927 1928 1929 1930 1931 1932 1933 1934 1935 1936 1937 1938 1939 1940 1941–1945 (WWII) 1946 1947 1948 1949 1950 1951 1952 1953 1954 1955 1956 1957 1958 1959 1960 1961 1962 1963 1964 1965 1966 1967 1968
Open Era	1969 1970 1971 1972 1973 1974 1975 1976 1977^J 1977^D 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 2018 2019 2020 2021 2022 2023 2024