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Tazehabad-e Markazi

Coordinates: 34°59′40″N 46°24′26″E / 34.99444°N 46.40722°E / 34.99444; 46.40722
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(Redirected from Tazeh Deh, Kermanshah)
Tazehabad-e Markazi
تازه ابادمركزي
village
Tazehabad-e Markazi is located in Iran
Tazehabad-e Markazi
Tazehabad-e Markazi
Coordinates: 34°59′40″N 46°24′26″E / 34.99444°N 46.40722°E / 34.99444; 46.40722
Country Iran
ProvinceKermanshah
CountyPaveh
BakhshCentral
Rural DistrictShamshir
Population
 (2006)
 • Total58
Time zoneUTC+3:30 (IRST)
 • Summer (DST)UTC+4:30 (IRDT)

Tazehabad-e Markazi (Persian: تازه ابادمركزي, also Romanized as Tāzehābād-e Markazī; also known as Tāzeh Deh)[1] is a village in Shamshir Rural District, in the Central District of Paveh County, Kermanshah Province, Iran. At the 2006 census, its population was 58, in 13 families.[2]

References

[edit]
  1. ^ Tazehabad-e Markazi can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3797870" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)" (Excel). Statistical Center of Iran. Archived from the original on 2011-09-20.