Jump to content

Taʻū County

Coordinates: 14°13′48″S 169°30′58″W / 14.230°S 169.516°W / -14.230; -169.516
From Wikipedia, the free encyclopedia
(Redirected from Ta'u County)

Taʻū County is a county in the Manu'a District in American Samoa.[1][2][3]

Demographics

[edit]
Historical population
YearPop.±%
1912480—    
1920551+14.8%
1930562+2.0%
1940754+34.2%
1950771+2.3%
1960720−6.6%
1970540−25.0%
1980468−13.3%
1990436−6.8%
2000380−12.8%
2010358−5.8%
2020236−34.1%
U.S. Decennial Census[4]

Ta'u County was first recorded beginning with the 1912 special census. Regular decennial censuses were taken beginning in 1920.[5] Its population zenith was in 1950, with 771 residents. It has since declined to its lowest point since the census began recording, just 358 residents. Manu'a District as a whole has similarly declined in population since that time.

Villages

[edit]

References

[edit]
  1. ^ "CPH-T-8. Population, Housing Units, Land Area, and Density for U.S. Island Areas: 2010" (PDF). United States Census. Retrieved 4 February 2019.
  2. ^ 1987 Census of Agriculture: Geographic area series, Parts 55-56. Bureau of the Census. 1991. p. 4.
  3. ^ "5.0102 Division of districts into counties". www.asbar.org.
  4. ^ "U.S. Decennial Census". Census.gov. Retrieved June 6, 2013.
  5. ^ "1920 Census: Outlying Possessions" (PDF). US Census Bureau. p. 1231. Retrieved 5 July 2022.

14°13′48″S 169°30′58″W / 14.230°S 169.516°W / -14.230; -169.516