Jump to content

Spring Hill, Santa Rosa County, Florida

Coordinates: 30°46′03″N 86°56′30″W / 30.76750°N 86.94167°W / 30.76750; -86.94167
From Wikipedia, the free encyclopedia
(Redirected from Springhill, Florida)

Spring Hill, Florida
Spring Hill, Florida is located in Florida
Spring Hill, Florida
Spring Hill, Florida
Spring Hill, Florida is located in the United States
Spring Hill, Florida
Spring Hill, Florida
Coordinates: 30°46′03″N 86°56′30″W / 30.76750°N 86.94167°W / 30.76750; -86.94167
CountryUnited States
StateFlorida
CountySanta Rosa
Area
 • Total
12.523 sq mi (32.43 km2)
 • Land12.521 sq mi (32.43 km2)
 • Water0.002 sq mi (0.005 km2)
Elevation
200 ft (60 m)
Population
 • Total
169
 • Density13/sq mi (5.2/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code850
GNIS feature ID294934[2]

Spring Hill (also known as Springhill) is an unincorporated community and census-designated place in Santa Rosa County, Florida, United States. Its population was 169 at the 2020 census,[3] up from 160 at the 2010 census.[1] It is part of the PensacolaFerry PassBrent, Florida Metropolitan Statistical Area.

Geography

[edit]

According to the U.S. Census Bureau, the community has an area of 12.523 square miles (32.43 km2); 12.521 square miles (32.43 km2) of its area is land, and 0.002 square miles (0.0052 km2) is water.[1]

References

[edit]
  1. ^ a b c d "2010 Census Gazetteer Files - Places: Florida". U.S. Census Bureau. Retrieved March 26, 2017.
  2. ^ "Spring Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior.
  3. ^ "Explore Census Data". data.census.gov. Retrieved May 13, 2024.