Jump to content

Špišić Bukovica

From Wikipedia, the free encyclopedia
(Redirected from Spisic Bukovica)
Špišić Bukovica
Špišić Bukovica is located in Croatia
Špišić Bukovica
Location of Špišić Bukovica in Croatia
Coordinates: 45°51′N 17°18′E / 45.85°N 17.3°E / 45.85; 17.3
Area
 • City107.8 km2 (41.6 sq mi)
 • Urban
32.4 km2 (12.5 sq mi)
Population
 (2021)[2]
 • City3,303
 • Density31/km2 (79/sq mi)
 • Urban
1,346
 • Urban density42/km2 (110/sq mi)
Websitespisicbukovica.hr

Špišić Bukovica is a municipality in Croatia in the Virovitica–Podravina County.

Demographics

[edit]

It has a total population of 4,221 (2011 census), in the following settlements:[3]

98.5% of the population are Croats, per census 2001.

Colonist settlements of Jova reka, Okrugljača, and Špišić Bukovica were established on the territory of the village municipality during the land reform in interwar Yugoslavia.[4]

History

[edit]

In the late 19th century and early 20th century, Špišić Bukovica was part of the Virovitica County of the Kingdom of Croatia-Slavonia.

References

[edit]
  1. ^ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata Q119585703.
  2. ^ "Population by Age and Sex, by Settlements" (xlsx). Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.
  3. ^ "Population by Age and Sex, by Settlements, 2011 Census: Špišić Bukovica". Census of Population, Households and Dwellings 2011. Zagreb: Croatian Bureau of Statistics. December 2012.
  4. ^ Šimončić-Bobetko, Zdenka (1990). "Kolonizacija u Hrvatskoj 1919.—1941. godine" [Colonization in Croatia Between 1919 and 1941]. Povijesni prilozi (in Croatian). 9 (9). Zagreb: Hrvatski institut za povijest: 160–162. ISSN 0351-9767.