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Gray's grasshopper warbler

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(Redirected from Sakhalin Warbler)

Gray's grasshopper warbler
Illustration by J. G. Keulemans (1881)
Scientific classification Edit this classification
Domain: Eukaryota
Kingdom: Animalia
Phylum: Chordata
Class: Aves
Order: Passeriformes
Family: Locustellidae
Genus: Helopsaltes
Species:
H. fasciolatus
Binomial name
Helopsaltes fasciolatus
(G. R. Gray, 1861)
Synonyms

Locustella fasciolata

Gray's grasshopper warbler (Helopsaltes fasciolatus), also known as Gray's warbler, is a species of grass warbler in the family Locustellidae; it was formerly included in the "Old World warbler" assemblage.

The Sakhalin grasshopper warbler was formerly considered conspecific.

Distribution and habitat

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This small passerine bird breeds in southern Siberia, northeastern China and Korea. It is migratory, wintering in southeast Asia. It is a species found in lowland and coastal regions, nesting in forests or thickets.

Description

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This is the largest of all the Locustella warblers, approaching the size of the great reed warbler. The adult has an unstreaked olive-brown back, uniformly grey breast and buff underparts, with unmottled dull orange undertail coverts.

The song is a short phrase, loud and distinctive; nothing like the insect-like reeling of European Locustella species, and more musical than that of Pallas's grasshopper warbler.

References

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  1. ^ BirdLife International (2012). "Locustella fasciolata". IUCN Red List of Threatened Species. 2012. Retrieved 26 November 2013.