Lazu (Mureș)
(Redirected from Rapolţel River)
| Lazu Láz-patak | |
|---|---|
  | |
| Location | |
| Country | Romania |
| Counties | Hunedoara County |
| Villages | Rapolțel, Rapoltu Mare |
| Physical characteristics | |
| Mouth | Mureș |
• location | Rapoltu Mare |
• coordinates | 45°51′08″N 23°04′53″E / 45.8521°N 23.0815°E |
| Length | 11 km (6.8 mi) |
| Basin size | 19 km2 (7.3 sq mi) |
| Basin features | |
| Progression | Mureș→ Tisza→ Danube→ Black Sea |
The Lazu (Hungarian: Láz-patak) is a right tributary of the river Mureș in Transylvania, Romania.[1][2] It discharges into the Mureș in Rapoltu Mare. Its length is 11 km (6.8 mi) and its basin size is 19 km2 (7.3 sq mi).[2] Its name originates from the Hungarian[citation needed], means “Fever Creek”.
References
[edit]- ^ "Planul național de management. Sinteza planurilor de management la nivel de bazine/spații hidrografice, anexa 7.1" (PDF, 5.1 MB). Administrația Națională Apele Române. 2010. p. 413.
- ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 178. OCLC 895459847. River code: IV.1.116c
