Berivoi
Appearance
(Redirected from Râuleţu)
Berivoi | |
---|---|
Location | |
Country | Romania |
Counties | Brașov County |
Villages | Berivoi, Făgăraș |
Physical characteristics | |
Mouth | Racovița |
• location | Făgăraș |
• coordinates | 45°50′01″N 24°57′35″E / 45.8337°N 24.9597°E |
Length | 29 km (18 mi) |
Basin size | 80 km2 (31 sq mi) |
Basin features | |
Progression | Racovița→ Olt→ Danube→ Black Sea |
Tributaries | |
• right | Dăculea, Copăcioasa |
The Berivoi (also: Făgărășel)[1] is a right tributary of the river Racovița in Romania.[2][3] It discharges into the Racovița in the city Făgăraș.[4] Its length is 29 km (18 mi) and its basin size is 80 km2 (31 sq mi).[3]
References
[edit]- ^ Municipiul Făgăraș
- ^ "Planul național de management. Sinteza planurilor de management la nivel de bazine/spații hidrografice, anexa 7.1" (PDF, 5.1 MB). Administrația Națională Apele Române. 2010. p. 676.
- ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 282. OCLC 895459847. River code: VIII.1.89.1
- ^ Berivoi / Berivoiul / Fagarasel (jud. Brasov), e-calauza.ro