Yeylaq Marshun
(Redirected from Margun, Zanjan)
Yeylaq Marshun
ييلاق مرشون | |
|---|---|
village | |
  Yeylaq Marshun | |
| Coordinates: 36°18′11″N 49°23′34″E / 36.30306°N 49.39278°E | |
| Country |  Iran |
| Province | Zanjan |
| County | Abhar |
| Bakhsh | Central |
| Rural District | Howmeh |
| Population (2006) | |
| • Total | 432 |
| Time zone | UTC+3:30 (IRST) |
| • Summer (DST) | UTC+4:30 (IRDT) |
Yeylaq Marshun (Persian: ييلاق مرشون, also Romanized as Yeylāq Marshūn; also known as Marchīn, Marchon, Marchūn, Margun, and Marshūn)[1] is a village in Howmeh Rural District, in the Central District of Abhar County, Zanjan Province, Iran. At the 2006 census, its population was 432, in 77 families.[2]
References
[edit]- ^ Yeylaq Marshun can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3074178" in the "Unique Feature Id" form, and clicking on "Search Database".
- ^ "Census of the Islamic Republic of Iran, 1385 (2006)" (Excel). Statistical Center of Iran. Archived from the original on 2011-09-20.
 | This Abhar County location article is a stub. You can help Wikipedia by expanding it. |