Lupul (Tazlău)
(Redirected from Lupul River (Tazlau))
| Lupul | |
|---|---|
  | |
| Location | |
| Country | Romania |
| Counties | Bacău County |
| Villages | Albele, Poiana |
| Physical characteristics | |
| Mouth | Tazlău |
• location | Poiana |
• coordinates | 46°22′42″N 26°42′57″E / 46.37833°N 26.71583°E |
• elevation | 230 m (750 ft) |
| Length | 9 km (5.6 mi) |
| Basin size | 17 km2 (6.6 sq mi) |
| Basin features | |
| Progression | Tazlău→ Trotuș→ Siret→ Danube→ Black Sea |
The Lupul is a right tributary of the river Tazlău in Romania.[1][2] It flows into the Tazlău in Poiana. Its length is 9 km (5.6 mi) and its basin size is 17 km2 (6.6 sq mi).[1]
References
[edit]- ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 410. OCLC 895459847. River code: XII.1.69.33.18
- ^ Ovidiu Gabor - "Economic Mechanism in Water Management" (PDF). Archived from the original (PDF) on 5 March 2009., map page 10
