Holmium(III) telluride
Appearance
(Redirected from Holmium sesquitelluride)
Identifiers | |
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3D model (JSmol)
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Properties | |
Ho2Te3 | |
Molar mass | 712.66 g·mol−1 |
Melting point | 1600 K[1] |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Holmium(III) telluride is an inorganic compound, one of the tellurides of holmium, with the chemical formula Ho2Te3.[1]
Preparation
[edit]Holmium(III) telluride can be obtained by reacting tellurium and holmium in a stoichiometric ratio:[2]
- 2 Ho + 3 Te → Ho2Te3
Properties
[edit]Holmium(III) telluride can be dissolved in indium(III) telluride to form a solid solution containing HoInTe3 phase (peritectic temperature 890 K):[3]
- Ho2Te3 + In2Te3 → 2 HoInTe3
References
[edit]- ^ a b Sadygov, F. M.; Mammadova, S. G.; Dzhafarova, Y. K.; Kuliyeva, S. A.; Ismailov, Z. I. Investigation of phase equilibrium in the Ho-Te system(in Azerbaijani). Azerbaidzhanskii Khimicheskii, 2010. 2: 113-115. ISSN 0005-2531.
- ^ J. P. Dismukes, J. G. White (Jul 1965). "Rare Earth Sesquiselenides and Sesquitellurides with the Sc 2 S 3 Structure". Inorganic Chemistry. 4 (7): 970–973. doi:10.1021/ic50029a010. ISSN 0020-1669. Archived from the original on 2023-05-10. Retrieved 2023-06-13.
- ^ Akhmedova, J. A.; Agaev, A. B.; Rustamov, P. G. Indium sesquitelluride-holmium sesquitelluride system(in Russian). Neorganicheskie Materialy, 1992. 28 (2): 2009-2010. ISSN 0002-337X.