Alfred Huber (tennis)
(Redirected from Fredl Huber)
 Alfred Huber in 1957 | |
| Country (sports) |  Austria |
|---|---|
| Born | 15 May 1930 Vienna, Austria |
| Died | 25 May 1972 (aged 42) |
| Singles | |
| Grand Slam singles results | |
| Wimbledon | 3R (1950, 1952, 1955) |
| Doubles | |
| Grand Slam doubles results | |
| Wimbledon | QF (1953) |
| Grand Slam mixed doubles results | |
| Wimbledon | 4R (1952, 1953) |
Alfred "Freddie" Huber (15 May 1930 – 25 May 1972) was an Austrian tennis and ice hockey player. He began his tennis career in 1946. He won the British Covered Court Championships in 1956. He competed at Wimbledon in 1949–57, but never advanced through the third round.[1] He competed in the hockey tournament at the 1948 Winter Olympics.[2]
References
[edit]- ^ "Alfred (Freddie) Huber". tennisarchives.com. Retrieved 5 January 2015.
- ^ Evans, Hilary; Gjerde, Arild; Heijmans, Jeroen; Mallon, Bill; et al. "Fredl Huber Olympic Results". Olympics at Sports-Reference.com. Sports Reference LLC. Archived from the original on 17 April 2020. Retrieved 12 May 2019.
External links
[edit]
Wikimedia Commons has media related to Alfred Huber.
- Alfred Huber at EliteProspects.com
- Alfred Huber at the Association of Tennis Professionals
- Alfred Huber at the International Tennis Federation
- Alfred Huber at TennisArchives.com
- Alfred Huber at tennisabstract.com
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