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This image shows some kind of formula that could be converted to TeX. Storing formulas as images makes it harder to change them. TeX also helps making sure that they all use the same font and size. A replacement has been proposed: ${\displaystyle {\text{please see below}}}$ In your article, replace the image with: <math>\text{please see below}</math> Deutsch ∙ English ∙ italiano ∙ magyar ∙ Nederlands ∙ polski ∙ sicilianu ∙ svenska ∙ Ελληνικά ∙ български ∙ македонски ∙ русский ∙ 日本語 ∙ فارسی ∙ +/−

<math>\begin{align}
 &\vec F = \frac{\mathrm d \vec p}{\mathrm d t} = m \vec a \; , \;
  \vec L = \vec r \times \vec p\\
 &\vec \nabla \cdot \vec E = 4 \pi \rho \; , \;
  \vec \nabla \times \vec E = - \frac 1 c \frac{\partial \vec B}{\partial t}\\
 &\vec \nabla \cdot \vec B = 0 \; , \;
  \vec \nabla \times \vec B = \frac 1 c \frac{\partial \vec E}{\partial t} + \frac{4 \pi}{c} \vec j\\
 &S = k_B \log \Gamma \; , \;
  PV = N k_B T\\
 &E = \sqrt{p^2 c^2 + \left( m c^2 \right)^2} \; , \;
  G^{\mu \nu} = \frac{8 \pi G}{c^4} T^{\mu \nu}\\
 &E = \hbar \omega = h \nu \; , \;
  L^2 = \hbar^2 l (l + 1)\\
 &\mathrm i \hbar \frac{\partial}{\partial t} | \psi \rangle = \hat H | \psi \rangle \; , \;
  (\mathrm i \hbar \!\not\!\partial - mc) \psi = 0
\end{align}</math>

${\displaystyle {\begin{aligned}&{\vec {F}}={\frac {\mathrm {d} {\vec {p}}}{\mathrm {d} t}}=m{\vec {a}}\;,\;{\vec {L}}={\vec {r}}\times {\vec {p}}\\&{\vec {\nabla }}\cdot {\vec {E}}=4\pi \rho \;,\;{\vec {\nabla }}\times {\vec {E}}=-{\frac {1}{c}}{\frac {\partial {\vec {B}}}{\partial t}}\\&{\vec {\nabla }}\cdot {\vec {B}}=0\;,\;{\vec {\nabla }}\times {\vec {B}}={\frac {1}{c}}{\frac {\partial {\vec {E}}}{\partial t}}+{\frac {4\pi }{c}}{\vec {j}}\\&S=k_{B}\log \Gamma \;,\;PV=Nk_{B}T\\&E={\sqrt {p^{2}c^{2}+\left(mc^{2}\right)^{2}}}\;,\;G^{\mu \nu }={\frac {8\pi G}{c^{4}}}T^{\mu \nu }\\&E=\hbar \omega =h\nu \;,\;L^{2}=\hbar ^{2}l(l+1)\\&\mathrm {i} \hbar {\frac {\partial }{\partial t}}|\psi \rangle ={\hat {H}}|\psi \rangle \;,\;(\mathrm {i} \hbar \!\not \!\partial -mc)\psi =0\end{aligned}}}$

DescriptionPhysicsEqs01.gif	Physical Equations
Date	1 February 2008, 19:46 (UTC)
Source	Own work
Author	MathKnight 19:46, 1 February 2008 (UTC)
Permission (Reusing this file)	Public domainPublic domainfalsefalse This work has been released into the public domain by its author, MathKnight. This applies worldwide. In some countries this may not be legally possible; if so: MathKnight grants anyone the right to use this work for any purpose, without any conditions, unless such conditions are required by law.

I, the copyright holder of this work, release this work into the public domain. This applies worldwide. In some countries this may not be legally possible; if so: I grant anyone the right to use this work for any purpose, without any conditions, unless such conditions are required by law.