File:Monty Hall problem game theory.png
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| Description |
The Monty Hall problem describes a game show with 3 doors. Behind one door is a car and behind the other 2 doors are goats. The probability of choosing the car-door at the start is 1/3. The probability of choosing a goat-door is 2/3. Note that there is no need to distingush between the two goat doors, they are equal.
It's better not to change in case 1 and it's better to change in case 2. As you don't known in which case you are and case 2 is more likely (2/3 prob) you should always change. That makes an overall-probability of 2/3*1 = 2/3 to win when you change, while not changing gives you 1/3*1 = 1/3 chance to win. |
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| Author | Unify |
| Permission (Reusing this file) |
public domain |
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 17:44, 20 March 2008 | | 998 × 685 (46 KB) | Unify~commonswiki | {{Information |Description=The Monty Hall problem describes a game show with 3 doors. Behind one door is a car and behind the other 2 doors are goats. The probability of choosing the car-door at the start is 1/3. The probability of choosing a goat-door is |
| 17:44, 20 March 2008 |  | 998 × 685 (46 KB) | Unify~commonswiki | {{Information |Description=The Monty Hall problem describes a game show with 3 doors. Behind one door is a car and behind the other 2 doors are goats. The probability of choosing the car-door at the start is 1/3. The probability of choosing a goat-door is |
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