File:Enrique Gottel.jpg

Picture portrait of Enrique Gottel. Author and date are unknown.

Source: [1]

• Displays portrait of person in question.
• Used only in said article for and is being used strictly for informational and/or educational purposes

1. It in no way infringes or assists in the illegal reproduction or distribution of the content.

• Image/Portrait is over 130 years old.
• No free images have been found of the subject
• This person died in 1875 therefore, a free alternative image cannot be used to replace this image.

This work is copyrighted (or assumed to be copyrighted) and unlicensed. It does not fall into one of the blanket acceptable non-free content categories listed at Wikipedia:Non-free content § Images or Wikipedia:Non-free content § Audio clips, and it is not covered by a more specific non-free content license listed at Category:Wikipedia non-free file copyright templates. However, it is believed that the use of this work: To illustrate the subject in question Where no free equivalent is available or could be created that would adequately give the same information On the English-language Wikipedia, hosted on servers in the United States by the non-profit Wikimedia Foundation, qualifies as fair use under United States copyright law. Any other uses of this image, on Wikipedia or elsewhere, may be copyright infringement. See Wikipedia:Non-free content and Wikipedia:Copyrights. Fair use //en.wikipedia.org/wiki/File:Enrique_Gottel.jpg true

To the uploader: Please add a detailed non-free use rationale for each article the image is used in, which must also declare compliance with the other parts of the non-free content criteria, as well as the source of the work and copyright information. For example non-free use rationales, see Wikipedia:Use rationale examples. Template:Non-free use rationale may be helpful for stating the rationale. This tag is not a sufficient claim of fair use. To patrollers and administrators: If this image has an appropriate rationale please append |image has rationale=yes as a parameter to the license template.