Jump to content

Felipe Augusto (footballer, born 1993)

From Wikipedia, the free encyclopedia
(Redirected from Felipe Augusto de Abreu)

Felipe Augusto
Personal information
Full name Felipe Augusto de Abreu
Date of birth (1993-08-31) 31 August 1993 (age 31)
Place of birth Rio de Janeiro, Brazil
Height 1.70 m (5 ft 7 in)
Position(s) Forward
Team information
Current team
Rio Tinto
Number 17
Youth career
2011 Serrano
2012 Braga
Senior career*
Years Team Apps (Gls)
2012 Vidago 10 (0)
2013 Tourizense 10 (0)
2013–2018 Vizela 123 (10)
2018–2019 Trofense 28 (5)
2019–2020 Varzim 1 (0)
2020Trofense (loan) 6 (0)
2021–2022 Ribeirão 13 (1)
2022 Serzedelo 8 (0)
2022– Rio Tinto 10 (0)
*Club domestic league appearances and goals, correct as of 18:22, 10 June 2023 (UTC)

Felipe Augusto de Abreu, known as Felipe Augusto or Felipe Abreu (born 31 August 1993) is a Brazilian football player who plays for Rio Tinto.

Club career

[edit]

He made his professional debut in the Segunda Liga for Vizela on 6 August 2016 in a game against Académico de Viseu.[1]

References

[edit]
  1. ^ "Game Report by Soccerway". Soccerway. 6 August 2016.
[edit]