Jump to content

Feit–Thompson conjecture

From Wikipedia, the free encyclopedia
(Redirected from Feit-thompson conjecture)

In mathematics, the Feit–Thompson conjecture is a conjecture in number theory, suggested by Walter Feit and John G. Thompson (1962). The conjecture states that there are no distinct prime numbers p and q such that

divides .

If the conjecture were true, it would greatly simplify the final chapter of the proof (Feit & Thompson 1963) of the Feit–Thompson theorem that every finite group of odd order is solvable. A stronger conjecture that the two numbers are always coprime was disproved by Stephens (1971) with the counterexample p = 17 and q = 3313 with common factor 2pq + 1 = 112643.

It is known that the conjecture is true for q = 2 (Stephens 1971) and q = 3 (Le 2012).

Informal probability arguments suggest that the "expected" number of counterexamples to the Feit–Thompson conjecture is very close to 0, suggesting that the Feit–Thompson conjecture is likely to be true.

See also

[edit]

References

[edit]
  • Feit, Walter; Thompson, John G. (1962), "A solvability criterion for finite groups and some consequences", Proc. Natl. Acad. Sci. U.S.A., 48 (6): 968–970, Bibcode:1962PNAS...48..968F, doi:10.1073/pnas.48.6.968, JSTOR 71265, PMC 220889, PMID 16590960 MR0143802
  • Feit, Walter; Thompson, John G. (1963), "Solvability of groups of odd order" (PDF), Pacific J. Math., 13: 775–1029, doi:10.2140/pjm.1963.13.775, ISSN 0030-8730, MR 0166261
  • Le, Mao Hua (2012), "A divisibility problem concerning group theory", Pure Appl. Math. Q., 8 (3): 689–691, doi:10.4310/PAMQ.2012.v8.n3.a5, ISSN 1558-8599, MR 2900154
  • Stephens, Nelson M. (1971), "On the Feit–Thompson conjecture", Math. Comp., 25 (115): 625, doi:10.2307/2005226, JSTOR 2005226, MR 0297686
[edit]