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Lambertia fairallii

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(Redirected from Fairall's honey-suckle)

Lambertia fairallii
Scientific classification Edit this classification
Kingdom: Plantae
Clade: Tracheophytes
Clade: Angiosperms
Clade: Eudicots
Order: Proteales
Family: Proteaceae
Genus: Lambertia
Species:
L. fairallii
Binomial name
Lambertia fairallii

Lambertia fairallii, commonly known as Fairall's honeysuckle, is a shrub which is endemic to the south-west of Western Australia.[1]

The species was formally described in 1983 by botanist Greg Keighery.[1][2]

Description

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A description of L. fairallii is given in Florabase.[3]

References

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  1. ^ a b c "Lambertia fairallii". Australian Plant Name Index (APNI), IBIS database. Centre for Plant Biodiversity Research, Australian Government, Canberra. Retrieved 31 January 2015.
  2. ^ a b Keighery, G.J. 1983. New species from the Stirling Range of Western Australia. Botanische Jahrbücher für Systematik, Pflanzengeschichte und Pflanzengeographie 104(2): 180, fig. 3
  3. ^ "Florabase: Lambertia fairallii". Western Australian Herbarium. Retrieved 31 January 2015. Retrieved 26 March 2018.