De damescoupeur - Wikipedia

This article needs additional citations for verification. Please help improve this article by adding citations to reliable sources. Unsourced material may be challenged and removed.
Find sources: "De damescoupeur" – news · newspapers · books · scholar · JSTOR (April 2019) (Learn how and when to remove this message)

You can help expand this article with text translated from the corresponding article in Dutch. (May 2009) Click [show] for important translation instructions.

Machine translation, like DeepL or Google Translate, is a useful starting point for translations, but translators must revise errors as necessary and confirm that the translation is accurate, rather than simply copy-pasting machine-translated text into the English Wikipedia.
Do not translate text that appears unreliable or low-quality. If possible, verify the text with references provided in the foreign-language article.
You must provide copyright attribution in the edit summary accompanying your translation by providing an interlanguage link to the source of your translation. A model attribution edit summary is Content in this edit is translated from the existing Dutch Wikipedia article at [[:nl:De damescoupeur]]; see its history for attribution.
You may also add the template {{Translated|nl|De damescoupeur}} to the talk page.
For more guidance, see Wikipedia:Translation.

De damescoupeur
Directed by	Maurits Binger
Written by	Hans Nesna
Produced by	Maurits Binger
Release date	31 October 1919 (1919-10-31)
Country	Netherlands
Language	Silent

De damescoupeur is a 1919 Dutch silent comedy film directed by Maurits Binger.

Cast

[edit]

Cor Ruys - Jacques, de damescoupeur
Henny Schroeder - Mevr. Georgette
Jeanne Van der Pers - Lily
Paula de Waart - Polly
Kitty Kluppell - Mannequin
Yvonne George - Mannequin

External links

[edit]

De damescoupeur at IMDb

This article related to a Dutch silent film is a stub. You can help Wikipedia by expanding it.

This 1910s comedy film–related article is a stub. You can help Wikipedia by expanding it.