Battle of Azua
Appearance
(Redirected from Battle of 19 March)
Battle of March 19 | |||||||
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Part of the Dominican War of Independence | |||||||
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Belligerents | |||||||
Dominican Republic | Haiti | ||||||
Commanders and leaders | |||||||
Gen. Pedro Santana Gen. Antonio Duvergé |
Gen. Charles Rivière-Hérard Gen. Souffrand | ||||||
Strength | |||||||
2,200 regulars 2 artillery pieces | 10,000 regulars | ||||||
Casualties and losses | |||||||
2 killed, 3 wounded[1] | 1,000 killed[1] |
The Battle of Azua (Spanish: Batalla de Azua) was the first major battle of the Dominican War of Independence and was fought on the 19 March 1844, at Azua de Compostela, Azua Province. A force of some 2,200 Dominican troops, a portion of the Army of the South, led by General Pedro Santana and General Antonio Duvergé defeated an outnumbering force of 10,000 troops of the Haitian Army led by General Souffrand.[2]
References
[edit]- ^ a b Calhoun, John Caldwell; Wilson, Clyde Norman (1959). The Papers of John C. Calhoun, Volume 21. Univ of South Carolina Press. p. 61.
- ^ Authors, Multiple (2013). Imperial Wars 1815–1914. Amber Books Ltd. ISBN 9781782741251.