Jump to content

2019 Australian Open – Wheelchair women's doubles

From Wikipedia, the free encyclopedia
Wheelchair women's doubles
2019 Australian Open
Final
ChampionNetherlands Diede de Groot
Netherlands Aniek van Koot
Runner-upNetherlands Marjolein Buis
Germany Sabine Ellerbrock
Score5–7, 7–6(7–4), [10–8]
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends men women mixed
← 2018 · Australian Open · 2020 →

Diede de Groot and Aniek van Koot defeated the defending champion Marjolein Buis and her partner Sabine Ellerbrock in the final, 5–7, 7–6(7–4), [10–8] to win the women's doubles wheelchair tennis title at the 2019 Australian Open. It was their first step towards an eventual Grand Slam, and de Groot completed the career Grand Slam with the win.

Buis and Yui Kamiji were the defending champions, but did not participate together. Kamiji partnered Giulia Capocci, but was defeated in the semifinals by de Groot and van Koot.

Seeds

[edit]

Draw

[edit]

Key

[edit]

Draw

[edit]
First round Final
          
1 Netherlands Diede de Groot
Netherlands Aniek van Koot
6 6
Italy Giulia Capocci
Japan Yui Kamiji
2 0
1 Netherlands Diede de Groot
Netherlands Aniek van Koot
5 77 [10]
2 Netherlands Marjolein Buis
Germany Sabine Ellerbrock
7 64 [8]
South Africa Kgothatso Montjane
United Kingdom Lucy Shuker
6 1 [7]
2 Netherlands Marjolein Buis
Germany Sabine Ellerbrock
2 6 [10]

References

[edit]
General
Specific