Jump to content

1998 Chase Championships

From Wikipedia, the free encyclopedia
(Redirected from 1998 WTA Tour Championships)
1998 Chase Championships
DateNovember 16–22
Edition28th (singles) / 27th (doubles)
CategoryYear-end championships
Draw16S/8D
Prize money$2,000,000
SurfaceCarpet / indoor
LocationNew York City, United States
VenueMadison Square Garden
Champions
Singles
Switzerland Martina Hingis
Doubles
United States Lindsay Davenport / Belarus Natasha Zvereva
← 1997 · WTA Finals · 1999 →

The 1998 Chase Championships was a women's tennis tournament played on indoor carpet courts at Madison Square Garden in New York City, New York in the United States. It was the 27th edition of the year-end singles championships, the 23rd edition of the year-end doubles championships, and was part of the 1998 WTA Tour. The tournament was held from November 16 through November 22, 1998. Martina Hingis won the singles title and earned $500,000 first-prize money. It was the last edition of the tournament to be played in the best-of-five-set format for the final which it had used since 1984.[1]

Finals

[edit]

Singles

[edit]

Switzerland Martina Hingis defeated United States Lindsay Davenport, 7–5, 6–4, 4–6, 6–2.

  • It was Hingis' 14th title of the year and the 39th of her career.

Doubles

[edit]

United States Lindsay Davenport / Belarus Natasha Zvereva defeated France Alexandra Fusai / France Nathalie Tauziat, 6–7, 7–5, 6–3.

  • It was Davenport's 12th title of the year and the 43rd of her career. It was Zvereva's 8th title of the year and the 81st of her career.

References

[edit]
  1. ^ John Barrett, ed. (2000). ITF World of Tennis 2000. London: CollinsWillow. pp. 203–204. ISBN 9780002189460.
[edit]