Jump to content

1986 Amateur World Series

From Wikipedia, the free encyclopedia
(Redirected from 1986 Baseball World Cup)
1986 Amateur World Series
Tournament details
CountryNetherlands
Teams12
Final positions
Champions Cuba (17th title)
Runner-up South Korea
Third place Chinese Taipei
Fourth place United States
← 1984
1988 →

The 1986 Amateur World Series was the 29th Amateur World Series (AWS), an international Men's amateur baseball tournament. The tournament was sanctioned by the International Baseball Federation (IBAF). The tournament took place, for the first time, in the Netherlands, from July 19 to August 2, and was won by Cuba – its 18th AWS victory.

There were 12 participating countries.

This was the last time the IBAF titled it as the AWS; the next ten competitions were held under the name Baseball World Cup, then was replaced in 2015 by the quadrennial WBSC Premier12.

Final standings

[edit]
Pos Team W L
 Cuba 10 1
 South Korea 8 3
 Chinese Taipei 8 3
4  United States 7 4
5  Japan 6 5
6  Italy 6 5
7  Venezuela 5 6
8  Puerto Rico 5 6
9  Netherlands 5 6
10  Colombia 3 8
11  Netherlands Antilles 2 9
12  Belgium 1 10

Honors and awards

[edit]

Statistical leaders

[edit]

All-Star team

[edit]
Position Player
C Italy Roberto Bianchi
1B Cuba Antonio Muñoz
2B Cuba Antonio Pacheco
3B Cuba Omar Linares
SS South Korea Chung-il Ryu
OF Cuba Lourdes Gourriel
Cuba Víctor Mesa
Cuba Luis Casanova
P Cuba Pablo Abreu (LHP)
Chinese Taipei Ming-Shan Kang (RHP)

[1]

[edit]
  1. ^ a b c "Historia de la Copa Mundial/World Cup History I-X (1973-1988)". Baseball de Cuba (in Spanish). Archived from the original on 22 November 2011.