1905 Paris–Roubaix
Appearance
(Redirected from 1905 Paris-Roubaix)
Race details | ||||||||||
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Dates | 23 April 1905 | |||||||||
Stages | 1 | |||||||||
Distance | 268 km (166.5 mi) | |||||||||
Winning time | 8h 4' 15" | |||||||||
Results | ||||||||||
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The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]
Results
[edit]Rank | Cyclist | Time |
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1 | Louis Trousselier (FRA) | 8h 4' 15″ |
2 | René Pottier (FRA) | +7' 00″ |
3 | Henri Cornet (FRA) | +16' 00″ |
4 | Hippolyte Aucouturier (FRA) | +23' 00″ |
5 | Edouard Wattelier (FRA) | +48' 00″ |
6 | Claude Chapperon (FRA) | +57' 00″ |
7 | Alois Catteau (BEL) | +1hr 6' 00″ |
8 | Paul Chauvet (FRA) | +1hr 12' 00″ |
9 | Lazare Brault (FRA) | +1hr 20' 00″ |
10 | Louis Colsaet (FRA) | +1hr 20' 01″ |
References
[edit]- ^ "10th Paris – Roubaix, 1905". bikeraceinfo. Retrieved 27 February 2015.
- ^ a b "1905 » 10th Paris – Roubaix". ProCyclingStats. Retrieved 27 February 2015.