1879 Wimbledon Championship
Appearance
(Redirected from 1879 Wimbledon Championships - Singles)
1879 Wimbledon Championship | |
---|---|
Date | 7–16 July |
Edition | 3rd |
Category | Grand Slam |
Surface | Grass |
Location | Worple Road SW19, Wimbledon, London, United Kingdom |
Venue | All England Croquet and Lawn Tennis Club |
Champions | |
Singles | |
John Hartley |
The 1879 Wimbledon Championships took place on the outdoor grass courts at the All England Lawn Tennis and Croquet Club in Wimbledon, London, United Kingdom. The tournament ran from 7 July until 16 July.[1] It was the 3rd staging of the Wimbledon Championships, and the first Grand Slam tennis event of 1879.[2] The entry for the 1879 all comers' tournament was 45, of whom 36 were newcomers.[2] The all comers' final was watched by 1100 spectators.[2]
Singles
[edit]Final
[edit]John Hartley defeated Frank Hadow, walkover
- This was Hartley's first major.
All Comers' Final
[edit]John Hartley defeated Vere St. Leger Goold, 6–2, 6–4, 6–2 [3]
Second place match
[edit]Vere St. Leger Goold defeated Cecil Parr, 4–6, 6–2, 5–6, 6–4, 6–4 [2]
References
[edit]- ^ 2010 Wimbledon Compendium, by Alan Little (The All England Lawn Tennis and Croquet Club, Wimbledon, London)
- ^ a b c d 100 Years of Wimbledon, by Lance Tingay (Guinness Superlatives Ltd. 1977)
- ^ "Gentlemen's Singles Finals 1877-2016". wimbledon.com. Wimbledon Championships. Retrieved 29 June 2017.